4[c+3]=28

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Solution for 4[c+3]=28 equation:


Simplifying
4[c + 3] = 28

Reorder the terms:
4[3 + c] = 28
[3 * 4 + c * 4] = 28
[12 + 4c] = 28

Solving
12 + 4c = 28

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 4c = 28 + -12

Combine like terms: 12 + -12 = 0
0 + 4c = 28 + -12
4c = 28 + -12

Combine like terms: 28 + -12 = 16
4c = 16

Divide each side by '4'.
c = 4

Simplifying
c = 4

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